Optimal. Leaf size=233 \[ -\frac{(a+b x)^m (B e-A f) (c+d x)^{-m} \, _2F_1\left (1,-m;1-m;\frac{(b e-a f) (c+d x)}{(d e-c f) (a+b x)}\right )}{f^2 m}-\frac{(a+b x)^{m+1} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,m+1;m+2;-\frac{d (a+b x)}{b c-a d}\right ) (a B d f m-b (-A d f+B c f m+B d e))}{b f^2 m (m+1) (b c-a d)}-\frac{d (a+b x)^{m+1} (B e-A f) (c+d x)^{-m}}{f^2 m (b c-a d)} \]
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Rubi [A] time = 0.12704, antiderivative size = 220, normalized size of antiderivative = 0.94, number of steps used = 7, number of rules used = 5, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.172, Rules used = {157, 70, 69, 105, 131} \[ \frac{(a+b x)^m (B e-A f) (c+d x)^{-m} \, _2F_1\left (1,m;m+1;\frac{(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{f^2 m}-\frac{(a+b x)^m (B e-A f) (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,m;m+1;-\frac{d (a+b x)}{b c-a d}\right )}{f^2 m}+\frac{B (a+b x)^{m+1} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,m+1;m+2;-\frac{d (a+b x)}{b c-a d}\right )}{b f (m+1)} \]
Antiderivative was successfully verified.
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Rule 157
Rule 70
Rule 69
Rule 105
Rule 131
Rubi steps
\begin{align*} \int \frac{(a+b x)^m (A+B x) (c+d x)^{-m}}{e+f x} \, dx &=\frac{B \int (a+b x)^m (c+d x)^{-m} \, dx}{f}+\frac{(-B e+A f) \int \frac{(a+b x)^m (c+d x)^{-m}}{e+f x} \, dx}{f}\\ &=-\frac{(b (B e-A f)) \int (a+b x)^{-1+m} (c+d x)^{-m} \, dx}{f^2}+\frac{((b e-a f) (B e-A f)) \int \frac{(a+b x)^{-1+m} (c+d x)^{-m}}{e+f x} \, dx}{f^2}+\frac{\left (B (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m\right ) \int (a+b x)^m \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^{-m} \, dx}{f}\\ &=\frac{(B e-A f) (a+b x)^m (c+d x)^{-m} \, _2F_1\left (1,m;1+m;\frac{(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{f^2 m}+\frac{B (a+b x)^{1+m} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,1+m;2+m;-\frac{d (a+b x)}{b c-a d}\right )}{b f (1+m)}-\frac{\left (b (B e-A f) (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m\right ) \int (a+b x)^{-1+m} \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^{-m} \, dx}{f^2}\\ &=\frac{(B e-A f) (a+b x)^m (c+d x)^{-m} \, _2F_1\left (1,m;1+m;\frac{(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{f^2 m}-\frac{(B e-A f) (a+b x)^m (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,m;1+m;-\frac{d (a+b x)}{b c-a d}\right )}{f^2 m}+\frac{B (a+b x)^{1+m} (c+d x)^{-m} \left (\frac{b (c+d x)}{b c-a d}\right )^m \, _2F_1\left (m,1+m;2+m;-\frac{d (a+b x)}{b c-a d}\right )}{b f (1+m)}\\ \end{align*}
Mathematica [A] time = 0.136575, size = 174, normalized size = 0.75 \[ \frac{(a+b x)^m (c+d x)^{-m} \left (\left (\frac{b (c+d x)}{b c-a d}\right )^m \left (B f m (a+b x) \, _2F_1\left (m,m+1;m+2;\frac{d (a+b x)}{a d-b c}\right )-b (m+1) (B e-A f) \, _2F_1\left (m,m;m+1;\frac{d (a+b x)}{a d-b c}\right )\right )+b (m+1) (B e-A f) \, _2F_1\left (1,m;m+1;\frac{(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )\right )}{b f^2 m (m+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.068, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( Bx+A \right ) \left ( bx+a \right ) ^{m}}{ \left ( dx+c \right ) ^{m} \left ( fx+e \right ) }}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (b x + a\right )}^{m}}{{\left (f x + e\right )}{\left (d x + c\right )}^{m}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B x + A\right )}{\left (b x + a\right )}^{m}}{{\left (f x + e\right )}{\left (d x + c\right )}^{m}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (b x + a\right )}^{m}}{{\left (f x + e\right )}{\left (d x + c\right )}^{m}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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